12d^2+4d-12=0

Solution for 12d^2+4d-12=0 equation:

12d^2+4d-12=0

a = 12; b = 4; c = -12;
Δ = b2-4ac
Δ = 42-4·12·(-12)
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{37}}{2*12}=\frac{-4-4\sqrt{37}}{24}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{37}}{2*12}=\frac{-4+4\sqrt{37}}{24}
$